(x+1)(x+3)^2=2

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Solution for (x+1)(x+3)^2=2 equation: 



(x+1)(x+3)^2=2

We move all terms to the left:

(x+1)(x+3)^2-(2)=0

We multiply parentheses ..

(+x^2+3x+x+3)^2-2=0

We move all terms containing x to the left, all other terms to the right

(+x^2+3x+x+3)^2=2

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